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find 3 consecutive even integers such that the sum of the least integer and the middle integer is 48 more than the greatest integer

Respuesta :

Answer:

50, 52, 54

Step-by-step explanation:

we can set the least great integer as x, so the list is x, x+2, and x+4. (since they are even we add even numbers) We can write an equation: x+x+2-48=X+4 If we solve it, we get x=50

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