bbygirlmaddie
bbygirlmaddie
15-06-2018
Mathematics
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HELP ME PLEASE!!!!
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gmany
gmany
15-06-2018
[tex]2\sqrt5+3\sqrt5-\sqrt5=(2+3-1)\sqrt5=4\sqrt5\\\\\text{Answer:}\ 4\sqrt5[/tex]
Look at the square root like "x", then
[tex]2\sqrt5+3\sqrt5-\sqrt5=/2x+3x-x=4x/=4\sqrt5 [/tex]
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