Respuesta :

konrad509
[tex]|\Omega|=6^2=36\\ |A|=1\\\\ P(A)=\dfrac{1}{36}[/tex]
altavistard
Sounds like a joint event:  First toss produces a 6  AND THEN  second toss prOduces a 3.  These two events are completely independent.

P(6) = 1/6, and P(3) = 1/6

Thus, the probability of rolling a 6 the first time and a 3 the second time is
(1/6)(1/6) = 1/36.