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ΔH for the formation of CuCl2 from its elements is -220.1 kJ/mol. How many kJ are associated with the formation of 0.30 mole of CuCl2?

-66 kJ
-78 kJ
85 kJ
201 kJ

Respuesta :

0.3 * - 220.1 = - 66.03kJ
sebassandin

Answer:

[tex]\Delta _fH=-66.03kJ[/tex]

Explanation:

Hello,

In this case, by knowing the enthalpy of formation of the copper (II) chloride is -220.1kJ/mol and there are 0.3 moles of such compound, the resulting whole energy is obtained by multiplying those values as the moles define the total energy as shown below:

[tex]\Delta _fH=-220.1\frac{kJ}{mol}*0.30mol\\ \Delta _fH=-66.03kJ[/tex]

Best regards.

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