Daloster Daloster
  • 10-07-2018
  • Mathematics
contestada

What is the true solution to the equation below? ln e^lnx^2=2 ln 8?
A.x=2.
B.x=4.
C.x=8.
D.x=64

What is the true solution to the equation below ln elnx22 ln 8 Ax2 Bx4 Cx8 Dx64 class=

Respuesta :

konrad509
konrad509 konrad509
  • 10-07-2018
[tex]x\ \textgreater \ 0\\\\ \ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8\\ \ln x+\ln x^2=\ln 8^2\\ \ln (x\cdot x^2)=\ln 64\\ \ln x^3=\ln 64\\ x^3=64\\ x=4\Rightarrow \text {B} [/tex]
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xanxan2
xanxan2 xanxan2
  • 01-11-2018

The answer is x=4 which is B in edg

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