Respuesta :

Standard Form of the circle:  

[tex] x^{2} +(y-3) ^{2} =14[/tex]

For y:

y=3 (+/-) [tex] \sqrt{-x} ^{2} +14[/tex]

For x:

x=[tex] \sqrt{-y ^{2} } +6y+5 and - \sqrt{-y} ^{2} +6y+5[/tex]

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