Answer:
Collin initially have [tex]\£14[/tex]
Step-by-step explanation:
Let
x------> money that Brian had initially
y------> money that Collin had initially
we know that
[tex]\frac{x}{y}=\frac{7}{2}[/tex]
solve for x
[tex]x=\frac{7}{2}y[/tex] -------> equation A
[tex]x-39=y-4[/tex] ------> equation B
substitute equation A in equation B
[tex]\frac{7}{2}y-39=y-4[/tex]
[tex]\frac{7}{2}y-y=39-4[/tex]
[tex]\frac{5}{2}y=35[/tex]
[tex]y=\£14[/tex]
