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A string with a mass of 8.00 g and a length of 5.00 m has one end attached to a wall; the other end is draped over a pulley and attached to a hanging object with a mass of 4.00 kg. If the string is plucked, what is the fundamental frequency of vibration?

Respuesta :

Answer:

f = [ 1/ 2L] √ [ T /u]  

u is the mass per unit length.  

u = 0.008 kg / 5m= 0.0016 kg/m  

T/u = 39.24 / 0.0016 =24525  

√ [ T /u] = 156.61  

f = [ 1/ 2L] √ [ T /u] = [1/ 2*5 ] *156.61  

f = 15.66 Hz

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