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A student solving a physics problem for the range of a projectile has obtained the expression
R= (v0^2)sin(2θ)/g
where v0=37.2meter/second, θ=14.1∘, and g=9.80 meter/second2. Use your calculator to evaluate R.

(A) 66.7 m
(B) 69.5 m
(C) 10.5 m
(D) 31.5 m

Respuesta :

Answer:

The range of the projectile is 66.7 meters.

Explanation:

The range of a projectile is given by the following expression as :

[tex]R=\dfrac{v_o^2\ sin2\theta}{g}[/tex]..............(1)

[tex]v_o=37.2\ m/s[/tex]

[tex]\theta=14.1^{\circ}[/tex]

[tex]g=9.8\ m/s^2[/tex]

The range can be calculated using equation (1). Putting the values of all parameters we get :

[tex]R=\dfrac{(37.2)^2\ sin2(14.1)}{9.8}[/tex]

R = 66.7 meters

So, the range of the projectile is 66.7 meters. Hence, this is the required solution.

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