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A fighter plane is flying overhead at mach 1.50. What angle does the wave front of the shock wave produced make relative to the plane's direction of motion (in degrees)?

Respuesta :

Answer:

 θ = 41.80°

Explanation:

Given that

Mach number M= 1.5

We know that

M = u/c

Where c is the velocity of sound and u is the speed of plane

c= 340 m/s

So

u = 1.5 x 340 m/s

u = 510 m/s

We know that

[tex]sin\theta =\dfrac{c}{u}[/tex]

Now by putting the values

[tex]sin\theta =\dfrac{c}{u}[/tex]

[tex]sin\theta =\dfrac{340}{510}[/tex]

 θ = 41.80°

So the angle will be 41.80°.

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