Answer:3.68 kg
Explanation:
Given
mass [tex]m_1=3 kg[/tex]
distance traveled by [tex]m_1[/tex] is 50 cm in 1 s
using [tex]s=ut+\frac{at^2}{2}[/tex]
[tex]0.50=0+\frac{a\cdot 1^2}{2}[/tex]
[tex]a=1 m/s^2[/tex]
Suppose T is the tension in string and [tex]m_2[/tex] is the mass of other body
For [tex]m_1[/tex]
[tex]T-m_1g=m_1a[/tex]
[tex]T=m_1(g+a)[/tex]
for other body
[tex]m_2g-T=m_2a[/tex]
[tex]T=m_2(g-a)[/tex]
Equating value of Tension
[tex]m_2=m_1\times \frac{g+a}{g-a}[/tex]
[tex]m_2=3\times \frac{10.8}{8.8}[/tex]
[tex]m_2=3.68 kg[/tex]
