A bumper car with a mass of 200 kilograms traveling at a velocity of 3.5 meters/second collides with a stationary bumper car with a mass of 250 kilograms. If the two bumper cars stick and move together at a velocity of 2.3 meters/second, what is the kinetic energy of the system after the collision

Respuesta :

Ek = (m·V²)/2
V - velocity of system after the collision
m = m1 + m2

Ek = (m1 + m2)·V²/2
Ek = (200 +250)·2,3²/2 = 450·5,29/2 = 1190,25 J