Answer:
Mass = 1.42 g
Explanation:
Given data:
Amount of heat absorbed = 4.56 j
Initial temperature = 29°C
Final temperature = 36°C
Mass of iron metal = ?
Specific heat capacity of iron = 0.46 j/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 36°C - 29°C
ΔT = 7°C
Q = m.c. ΔT
m = Q / c. ΔT
m = 4.56 j / 0.46 j/g°C . 7°C
m = 4.56 j /3.22 j/g
m = 1.42 g
