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Assume you stand between two loudspeakers that are excited by the same oscillator emitting a1150 Hz sound frequency. You stand at a distance of 4 m from one of the loudspeakers.I - What is the wavelength of the sound waves? Assume thatcs= 343 m/s. g

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xero099

Answer:

[tex]\lambda = 0.299\,m[/tex]

Explanation:

The wavelength of a wave is given by this expression:

[tex]v_{air} = \lambda\cdot f_{osc}[/tex]

[tex]\lambda = \frac{v_{air}}{f_{osc}}[/tex]

[tex]\lambda = \frac{343\,\frac{m}{s} }{1150\,Hz}[/tex]

[tex]\lambda = 0.299\,m[/tex]

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