Answer:
The period of the orbit is 12163.649 seconds.
Explanation:
What quantity are you looking for? I'll assume it's the orbital period.
The period, P, of an orbit in seconds is found from
P = 2π √[a³/(GM)]
where
a = the semimajor axis of an elliptical orbit, or the radius of a circular orbit
G = 6.67428e-11 m³ kg⁻¹ sec⁻²
M = the sum of the masses of Mars and the satellite
The mass of the satellite is presumably negligible.
M = 6.4191e+23 kg
a = 1.6 Rmars = 1.6 (3.397e+6 meters) = 5435200 m
Therefore,
P = 12163.649 sec
