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A package that weighs 300 lb is placed on an inclined plane. If a force of 10 lb is just sufficient to keep the package from sliding, find the angle of inclination of the plane. (Ignore the effects of friction. Round your answer to one decimal place.)

Respuesta :

Answer:

The angle of inclination of the plane [tex]\theta[/tex] = 1.91°

Step-by-step explanation:

Given data

W = 300 lb

Force sufficient to slide the box F = 10 lb

From the free body diagram

W [tex]\sin \theta[/tex] = F

Put the values in above formula we get

300 [tex]\sin \theta[/tex] = 10

[tex]\sin \theta[/tex] = 0.0333

[tex]\theta[/tex] = 1.91°

This is the angle of inclination of the plane.

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