Respuesta :

crisforp
5 * log ( 6 / 11 ) = 5 * ( log6 - log11 ) = 5 * [ log(2 * 3) - log11] = 5 * (log2 + log3 - log11 ).
We know that C log a = log a^C. 
We know that log (x/y) = log x - log y
We know that log xy = log x + log y
Therefore... log(6/11)^5 =
5 * log (6/11). Which can be expanded to...
5 (log 6 - log 11) ... 5 (log 3 + log 2 - log 11)

Its a law of logarithms. 

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