Answer:
After 3.06seconds
Explanation:
Given that the following data are
acceleration a= 3,2m/s^2
distance s=15m,
time t=?
Applying the formula for the equation of motion we have
s=ut+1/2at^2
we no initial velocity (u=0)
substituting our given values into the expression we have
15=0*t+1/2(3.2)t^2
15=1/2(3.2)t^2
15=3.2t^2/2
30=3.2t^2
t^2=30/3.2
t^2=9.375
Squaring both sides we have
t=√9.375
t=3.06seconds
It will take the sled 3.06 seconds to get to the bottom
