2250293 2250293
  • 06-11-2020
  • Mathematics
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If y varies directly with x and y= 12 when x= 16, what is the value of x when y= 5?

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Leora03
Leora03 Leora03
  • 06-11-2020

Answer:

[tex]x = 6 \frac{2}{3} [/tex]

Step-by-step explanation:

Since y varies directly with x,

y= kx, where k is a constant.

① Find the value of the constant k.

When y=12, x= 16,

12= k(16)

16k= 12

[tex]k = \frac{12}{16} \\ k = \frac{3}{4} [/tex]

②Substitute the value of k back into the equation:

[tex]y = \frac{3}{4} x[/tex]

③ Find value of x when y=5.

When y=5,

[tex]5 = \frac{3}{4} x \\ x = 5 \div \frac{3}{4} \\ x = 5 \times \frac{4}{3} \\ x = \frac{20}{3} \\ x = 6 \frac{2}{3}[/tex]

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