Answer:
b.
Explanation:
From the given information:
[tex]p = \dfrac{zM}{N_oa^3}[/tex]
where;
a = 0.41 nm = [tex]4.1 \times 10^{-8} \ cm[/tex]
M = 90.5 + 37.3 = 127.8 g/mol
[tex]N_o = 6.023 \times 10 ^{23}[/tex]
p = 3.15 g/cm³
∴
[tex]3.15 = \dfrac{z \times 127.8}{(6.02 \times 10^{23}) \times (4.1 \times 10^{-8} )^3}[/tex]
Z = 1
Thus, the ceramic material has a simple cubic crystal system and the crystal structure is possible to be Cesium chloride.
