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06-11-2016
Chemistry

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Molecular bromine is 24 percent dissociated at 1600 k and 1.00 bar in the equilibrium br2 (
g. = 2br (
g. calculate kp at 1600 k.

Respuesta :

Edufirst Edufirst

15-11-2016

Br2 == 2Br

24% dissociated => n total moles, 0.24 mol*n of Br, and 0.76*n mol of Br2

=> partial pressure of Br, P Br = 0.24 bar, and
partical pressure of Br2, P Br2 = 0.76 bar

kp = (P Br)^2 / P Br2 = (0.24)^2 / 0.76 = 0.0758

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