krystalcaudle krystalcaudle

07-11-2016
Mathematics

contestada

I need to factor 4n^2+4n-3. How??

Respuesta :

Аноним Аноним

07-11-2016

Simple.....

you have: [tex] 4n^{2} +4n-3[/tex]

What multiplies to -12 and adds to 4?

6*-2=-12

6+-2=4

If you plug it into the box method you should get...--->>>

(2n-1)(2n+3)

Thus, your answer.

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