A 200 g piece of iron is heated to 100°C. It is then dropped into water to bring its temperature down to 22°C. What is the amount of heat transferred to water?

Respuesta :

q = m * c * change in temp.
q = (200 g)(4.18 J/g*C)(22C - 100C)
q = -65208J
q = 65.208 kJ lost