Zn(s)+2HCl(aq)= Zncl2(aq)+H2(g)
0.306 moles of HCl are required to consume all of the Zn in the reaction mixture..
What is the volume of the solution that will deliver the required amount of the concentration is 2.5 M in HCl? What volume is required to prepare this solution from a concentrated (18m)?
There
are a number of ways to express concentration of a solution. This includes
molarity. Molarity is expressed as the number of moles of solute per volume of
the solution. We calculate as follows:
2.5 M HCl = 2.5 mol HCl / L soln
0.306 mol HCl / 2.5 mol HCl/L son = 0.1224 L soln needed
M1V1 = M2V2 18 M(V1) = 2.5 M(0.1224 L) V1 = 0.017 L of the 18 M solution
