The formation of aluminum chloride can be described by the balanced chemical equation. 2Al+3Cl2⟶2AlCl3 How many moles of Cl2 molecules are required to react with 3.90 mol Al atoms? moles of Cl2 required

Respuesta :

moles(AL)/moles(CL2) = 2/3

moles(CL2) = 3/2 * 3.90

moles(CL2) = 5.85 mol