Solve for x and y.

4^(x+y) = 64

2^(2x-y) = 128

A) x = 10/3, y = -1/3
B) x = -10/3, y = -1/3

[tex]4^{x+y}=64\Rightarrow x+y=3[/tex]
[tex]2^{2x-y}=128\Rightarrow 2x-y=7[/tex]

So we have
[tex]x+y=3[/tex]
[tex]2x-y=7[/tex]
Solve for [tex]x[/tex]:
[tex]3x=10[/tex]
[tex]\Rightarrow x=\frac{10}{3}[/tex]

Plug [tex]x[/tex] into one of the equations:
[tex]\frac{10}{3}+y=3[/tex]
[tex]\Rightarrow y=-\frac{1}{3}[/tex]

So the answer is
[tex]x=\frac{10}{3}, y=-\frac{1}{3}[/tex]

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PrettyAwesomeSmart PrettyAwesomeSmart · Answer 2 · 2017-01-11T01:05:27+01:00

PrettyAwesomeSmart PrettyAwesomeSmart

11-01-2017

4^10/3 + -1/3 will equal to 64
2^(2*10/3-1/3) will equal to 128

Your final answer is A. x = 10/3, y = -1/3

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Solve for x and y. 4^(x+y) = 64 2^(2x-y) = 128 A) x = 10/3, y = -1/3 B) x = -10/3, y = -1/3

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Solve for x and y.

4^(x+y) = 64

2^(2x-y) = 128

A) x = 10/3, y = -1/3
B) x = -10/3, y = -1/3