From a sample size of 169, it was determined that the 68% confidence interval for the population mean is (505, 517). Therefore, the sample mean was ___. and the margin of error was ___.

A. 511; 6
B. 511; 12
C. 513; 6
D. 513; 12

From a sample size of 169 it was determined that the 68 confidence interval for the population mean is 505 517 Therefore the sample mean was and the margin of e class=

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Answer:

A. 511; 6

Step-by-step explanation:

The margin of error would be [tex]\pm\frac{517-505}{2}=\pm\frac{12}{2}=\pm 6[/tex]

The sample mean would be [tex]505+6=511[/tex] (or [tex]517-6=511[/tex])