Answer:
226.08 ft³
Step-by-step explanation:
[tex]\textsf{volume of a cone}=\frac{1}{3}\pi r^2h[/tex]
(where [tex]r[/tex] = radius of the base and [tex]h[/tex] = height)
[tex]\textsf{radius}\ r=\frac{1}{2}\ \textsf{diameter}[/tex]
Given:
- diameter = 12ft ⇒ radius = 12 ÷ 2 = 6 ft
- height = 6ft
- [tex]\pi[/tex] ≈ 3.14
[tex]\implies \textsf{volume of tent}=\frac{1}{3}\times3.14 \times 6^2 \times 6=226.08 \ \textsf{ft}^3[/tex]
