the difference between two positive integers is 3. if the smaller is added to the square of the larger, the sum is 377. Find the integers

Respuesta :

Answer:

let the smaller number be x and the larger number is y

y =x+3

x+y²=377

x+(x+3)²=377

x+(x+3)(x+3)=377

x+x²+3x+3x+9=377

x²+7x+9-377=0

x²+7x-368=0

using factorization method

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