Two lenses, one converging with a focal length of 10.0 cm and one diverging with a focal length of -5.0 cm, are placed 13.0 cm apart, the position of the final image formed is mathematically given as
u=70.645
What is the position of the final image formed.?
Generally, the equation for the convex lens is mathematically given as
I/f=1/u-1/v
Therefore
1/20=1/u-(1/-61)
u=29.76cm
In conclusion, For concave lens
1/-10=1/u-1/8.76
u=87.6/1.2
u=70.645
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