Challenge A baseball player hits a baseball and its height is modeled by the function h(t)=-16t^2=12t+4. If t represents time, in seconds, find the time in seconds when the ball hit the ground
0=-16t^2+12t+4 use math to solve I will complete the square group t terms 0=(-16t^2+12t)+4 factor out quadratic coefient 0=-16(t^2-(3/4)t)+4 take 1/2 of linear coefient and squaer it (-3/4)/2=-3/8, (-3/8)^2=9/64 take negative and positive of it and add to inside of parenthasees 0=-16(t^2+(-3/4)t+9/64-9/64)+4 factor pefect square 0=-16((t-3/8)^2-9/64)+4 expand/distribute 0=-16(t-3/8)^2+9/4+4 0=-16(t-3/8)^2+25/4 add -16(t-3/8)^2 to both sides 16(t-3/8)^2=25/4 divide both sides by 16 (t-3/8)^2=25/64 sqrt both sides remmber positive and negative roots t-3/8=+/-5/8 add 3/8 to both sides t=3/8+/-5/8
t=3/8+5/8 or t=3/8-5/8 t=8/8 or t=-2/8 t=1 or -1/4 we can't have negative time so at t=1 1 second
