Answer:
[tex]x=1\text{ or }x=13[/tex]
Step-by-step explanation:
We have been given an equation [tex](x-7)^2=36[/tex]. We are asked to solve the given equation for x.
To solve our given equation, we will take square root of both sides of equation.
[tex]x-7=\pm\sqrt{36}[/tex]
[tex]x-7=\pm\sqrt{6^2}[/tex]
[tex]x-7=\pm 6[/tex]
[tex]x-7=-6\text{ or }x-7=6[/tex]
[tex]x-7+7=-6+7\text{ or }x-7+7=6+7[/tex]
[tex]x=1\text{ or }x=13[/tex]
Therefore, the solution for our given equation are [tex]x=1\text{ or }x=13[/tex].