A jet travels 2250 km westward at a speed of 960 km/hr. it then encounters a strong headwind and its speed drops to 805 km/hr for the next 1320 km of its westward trip. what is the average velocity for the trip?
For the first part of the trip: we have velocity = 960 km/hr and distance = 2250 km velocity = distance / time time1 = distance / velocity = 2250 / 960 = 2.34375 hours
For the second part of the trip: we have velocity = 805 km/hr and distance = 1320 km velocity = distance / time time2 = distance / velocity = 1320 / 805 = 1.63975 hours
For the total trip: we have: total distance covered = 2250 + 1320 = 3570 km total time taken = 2.34375 + 1.63975 = 3.9835 hours average velocity = total distance / total time average velocity = 3570 / 3.9835 = 896.1968 km/hr
