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  • 09-10-2017
  • Mathematics
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4sin theta + 3 square root of 3 = square root of 3

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ruhibreddy
ruhibreddy ruhibreddy
  • 09-10-2017
Solving for θ:

4sin
θ + 3√3 = √3

First subtract 3√3 from both sides:

4sin
θ = -2√3

Now, divide by 4:

sin
θ = (-2√3)/4
sin
θ = -√3/2

Using the unit circle we know that sin of -√3/2 is 240° or 4/3π and 300° or 5/3π

Hope this helps!


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