jacobe0008
jacobe0008 jacobe0008
  • 08-02-2018
  • Mathematics
contestada

Solve for f.

h = f² + 2g




f=h±2g−−√

f=h±g√2

​ f=±h+2g−−−−−√ ​

f=±h−2g−−

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Jr04
Jr04 Jr04
  • 13-02-2018
Solve for f.

h = f² + 2g

[tex]h= f^2+2g \\ \\ h-2g=f^2 \\ \\ \boxed{ \pm\sqrt{h-2g}= f} [/tex]
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