Respuesta :

[tex]\bf \textit{Logarithm of exponentials}\\\\ log_a\left( x^ b \right)\implies b\cdot log_a(x)\\\\ -------------------------------\\\\ 7^x=9\implies \boxed{log(7^x)=log(9)}\implies x\cdot log(7)=log(9) \\\\\\ x=\cfrac{log(9)}{log(7)}[/tex]

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