jcla000
jcla000
10-04-2018
Mathematics
contestada
Solve for x.
y=4+bx^2
Respuesta :
Аноним
Аноним
10-04-2018
[tex]y=4+bx^2[/tex]
[tex]bx^2 = y - 4[/tex]
[tex]x^2 = \dfrac{y-4}{b} [/tex]
[tex]x = \pm \sqrt{ \dfrac{y-4}{b} } [/tex]
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