[tex]\frac{2y - 5}{3} = \frac{4y - 1}{2}[/tex]
[tex]3(4y - 1) = 2(2y - 5)[/tex]
[tex]3(4y) - 3(1) = 2(2y) - 2(5)[/tex]
[tex]12y - 3 = 4y - 10[/tex]
[tex]8y - 3 = -10[/tex]
[tex]8y = -7[/tex]
[tex]\frac{8y}{8} = \frac{-7}{8}[/tex]
[tex]y = -0.875[/tex]
